SOLUTION: Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person.
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Question 230632: Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! Don is twice as old as Irene; Ed is 16 years older than Irene. The sum of all three of their ages is 60 years. Find the age of each person.
Step 1. Let x be the age of Irene.
Step 2. Let 2x be the age of Don since he'1 twice as old as Irene.
Step 3. Let x+16 be the age of Ed since he's 16 years older than Irene.
Step 4. Then, x+2x+x+16=60 since the sum of their ages is 60.
Step 5. Solving yields the following steps
Subtract 16 from both sides of the equation
Divide by 4 to both sides of the equation
, , . Note the sum of the ages equal to 60 years old.
Step 6. ANSWER: Irene is 11 years old, Don is 22 years old, and Ed is 27 years old.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
http://www.FreedomUniversity.TV