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Question 230583: I am working on mixture problems right now , here is an example of one that I can solve... A chemist has 40 ml. of a solution that is 50% acid. How much water should he add to make a solution that is 10% acid? My text book shows the steps to solve the problem.
.50(40) + 0 = .10(40+ x)
2000 = 400+ 10x
1600 = 10x
160= x
I can solve the problem when I have to decrease the percent. What I am having trouble with is when I am asked to INCREASE the percentage. Here is the problem I need help with.
If 800 ml of a juice drink is 15% grape juice, how much grape juice should be added to make a drink that is 20% grape juice? I am not sure where to start. I would appreciate any help that you have to offer.
Thanks,
Horus2
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! If 800 ml of a juice drink is 15% grape juice, how much grape juice should be added to make a drink that is 20% grape juice?
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The other 85% is water = 800*0.85 = 680 ml of water.
Add juice to make that 680 ml of water 80% of the solution.
If 680 ml is 80%, then the total solution is 680/0.8 = 850 ml
--> add 50 ml of juice.
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