SOLUTION: A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each coin do you have?

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each coin do you have?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 230463: A bag contains pennies and nickels only. If there are 182 coins in the bag and they add up to $3.90, how many of each coin do you have?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
p+n=182 or p=182-n
.01p+.05n=3.90
Replace p with (182-n) & solve for n.
.01(182-n)+.05n=3.90
1.82-.01n+.05n=3.90
.04n=3.90-1.82
.04n=2.08
n=2.08/.04
n=52 nickels.
182-52=130 pennies.
Proof:
.01*130+.05*52=3.90
1.30+2.60=3.90
3.90=3.90