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Question 230408: The first part is what I have to solve, and I do not no what I am doing. Especially what it says about exersice 107 I cannot solve that one either but does it have to be done in order to answer the top part of the question? HELP SOMEBODY please. I need help. I am not sure if this is a work problem or a square root problem either :(
Comparing wind chills. Use the formula from
Exercise 107 to determine who will feel colder:
a person in Minneapolis at 10°F with a 15-mph wind
or a person in Chicago at 20°F with a 25-mph wind.
107. Wind chill. The wind chill temperature W (how cold
the air feels) is determined by the air temperature t and
the wind velocity v. Through experimentation in
Antarctica, Paul Siple developed a formula for W:
W = 91.4 - (10.5+6.7sqrtv-0.45v)(457-5t)/110 (this is a fraction)
where W and t are in degrees Fahrenheit and v is in miles
per hour (mph).
a) Find W to the nearest whole degree when t = 25°F
and v = 20 mph.
b) Use the accompanying graph to estimate W when
t = 25°F and v = 30 mph.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Use the formula from
Exercise 107 to determine who will feel colder:
a person in Minneapolis at 10°F with a 15-mph wind
or a person in Chicago at 20°F with a 25-mph wind.
107. Wind chill. The wind chill temperature W (how cold
the air feels) is determined by the air temperature t and
the wind velocity v. Through experimentation in
Antarctica, Paul Siple developed a formula for W:
W = 91.4 - (10.5+6.7sqrtv-0.45v)(457-5t)/110 (this is a fraction)
Question: I see the denominator but where does the fraction start?
---------------------------------------------
where W and t are in degrees Fahrenheit and v is in miles
per hour (mph).
a) Find W to the nearest whole degree when t = 25°F
and v = 20 mph.
W = 91.4 - (10.5+6.7sqrt(20)-0.45(20))/110
----------------
Comment: I cannot see where the numerator for the fraction starts.
-----------------------------------------------------
b) Use the accompanying graph to estimate W when
t = 25°F and v = 30 mph.
Comment: Graph not provided.
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Cheers,
Stan H.
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