SOLUTION: The expensive ones cost 7$ each, whereas the worthless ones sold for only 2$ each. Monongahela spent $111 and bought 3 more expensive ones than worthless ones how many of each kin
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-> SOLUTION: The expensive ones cost 7$ each, whereas the worthless ones sold for only 2$ each. Monongahela spent $111 and bought 3 more expensive ones than worthless ones how many of each kin
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Question 230308: The expensive ones cost 7$ each, whereas the worthless ones sold for only 2$ each. Monongahela spent $111 and bought 3 more expensive ones than worthless ones how many of each kind did she buy? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 7(X+3)+2X=111
7X+21+2X=111
9X=111-21
9X=90
X=90/9
X=10 WORTHLESS ONES WERE BOUGHT.
10+3=13 EXPENSIVE ONES WERE BOUGHT.
7*13+2*10=111
91+20=111
111=111