SOLUTION: log 5+log (n+1)=log 6n 9 9 9

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Question 23014: log 5+log (n+1)=log 6n
9 9 9
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
log%289%2C5%29+%2B+log%289%2C%28n%2B1%29%29+=+log%289%2C6n%29

log%28b%2CM%29+%2B+log%28b%2CN%29+=+log%28b%2CMN%29, so log%289%2C5%29+%2B+log%289%2C%28n%2B1%29%29+=+log%289%2C5%28n%2B1%29%29

log%289%2C+5%28n%2B1%29%29+=+log%289%2C6n%29

If log%28b%2C+M%29+=+log%28b%2C+N%29, then M=N

5(n+1) = 6n
5n+5 = 6n

Subtract 5n from each side:
5= n
Remember to check the value of n to make sure you don't have a log of a negative number. You do not, so the answer n=5 is acceptable.

R^2 at SCC