SOLUTION: A freight train leaves a station traveling 60 miles per hour. Thirty minutes later a passenger train leaves the station in the same direction on a parallel track at a speed of 72 m

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Question 230087: A freight train leaves a station traveling 60 miles per hour. Thirty minutes later a passenger train leaves the station in the same direction on a parallel track at a speed of 72 miles per hour. How long will it take the passenger train to catch the freight train?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
In 30 min, the freight train has gone:
d+=+60%2A%281%2F2%29 mi
d+=+30 mi (it's headstart)
When the passenger train leaves the station, I start a stopwatch
and I'll stop it at time = t when trains meet
Let d%5Bp%5D = distance the passenger train has to
go to catch freight train
For passenger train:
(1) d%5Bp%5D+=+72t
For freight train:
(2) d%5Bp%5D+-+30+=+60t
Substitute (1) in (2)
72t+-+30+=+60t
12t+=+30
t+=+5%2F2
The passenger train catches the freight train in 2.5 hrs
check:
(1) d%5Bp%5D+=+72t
d%5Bp%5D+=+72%2A2.5
d%5Bp%5D+=+180 mi
and
(2) d%5Bp%5D+-+30+=+60t
d%5Bp%5D+=+60%2A2.5+%2B+30
d%5Bp%5D+=+150+%2B+30
d%5Bp%5D+=+180 mi
OK