Question 229957: Sam has 5 more dimes than quarters and four less nickels than quarters. If he has 34 coins, how many of each does he have? I started with # of dimes x + 5, # of quarters is x, # of nickels is x-4. I formed this equation .10(x+5) + .25x + .05 (x+4) = 34, then I multiplied by 100 to get 10x + 50 + 25x + 5x +20 = 34, 40x + 30 =34. I have no idea what I'm doing.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Sam has 5 more dimes than quarters and four less nickels than quarters.
d = q + 5
n = q -4
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If he has 34 coins, how many of each does he have?
n + d + q = 34
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Substitute for d and n and solve for "q":
q-4 + q+5 + q = 34
3q +1 = 34
3q = 33
q = 11 (# of quarters)
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d = q+5 = 16 (# of dimes)
n = q-4 = 7 (# of nickels)
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Cheers,
Stan H.
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