SOLUTION: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
I did not get the answer t
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I did not get the answer t
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Question 22995: If Sally can paint a house in 4 hours, and John can paint the same house in 6 hour, how long will it take for both of them to paint the house together?
I did not get the answer to this problem, so if you could please give me some solutions. Found 2 solutions by rapaljer, AnlytcPhil:Answer by rapaljer(4671) (Show Source):
You can put this solution on YOUR website! If Sally can paint the house in 4 hours, then in 1 hour she can paint 1/4 of the house.
If John can paint the house in 6 hours, then in 1 hour he can paint 1/6 of the house.
Let x = number of hours it would take them together to paint the house, then working together, in 1 hour they can paint 1/x of the house.
The equation is this:
Multiply both sides by the LCD which is 12x: = 2.4 hours
If Sally can paint a house in 4 hours, and John can paint the same house in 6
hour, how long will it take for both of them to paint the house together?
I did not get the answer to this problem, so if you could please give me some
solutions.
Let x = the number of hours it will take them painting together
Then their combined rate = (1 house)/(x hours) or 1/x house/hr
>>...Sally can paint a house in 4 hours...<<
Translation: Sally's rate is (1 house)/(4 hours) or 1/4 house/hr
>>...John can paint the same house in 6 hour...<<
Translation: John's rate is (1 house)/(6 hours) or 1/6 house/ hr
To form the equation:
Sally's rate + John's rate = their combined rate
1/4 + 1/6 = 1/x
Can you solve that? (Hint: get LCD = 12x and multiply thru)
Answer: 2.4 hours or 2 hours 24 minutes
Edwin
AnlytcPhil@aol.com
