Question 229589: assume that the perimeter of a pentagon whose perimeter is 4a+4 is three times the perimeter of a triangle whose perimeter is a+3.
a.)find a
b.)using your answer to 22A, calculate the perimeters of both the pentagon and the triangle.(if youve done your calculations correctly, the pentagons perimeter will be 3 times the perimeter of the triangle.)
c.)an octagon has the same perimeter as the pentagon you calculated in problem 22b. what is the length of each side of the octagon?
please please please help me i need help im desperate!!!!!!!!!!!!!!!!!!!!!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! assume that the perimeter of a pentagon whose perimeter is 4a+4 is three times the perimeter of a triangle whose perimeter is a+3.
a.)find a
(4a+4)= 3(a+3)
4a+4 = 3a+9
a = 5
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b.)using your answer to 22A, calculate the perimeters of both the pentagon and the triangle.(if youve done your calculations correctly, the pentagons perimeter will be 3 times the perimeter of the triangle.)
perimeter of pentagon = 4*5+4 = 24
perimeter of triangle = 5+3 = 8
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c.)an octagon has the same perimeter as the pentagon you calculated in problem 22b. what is the length of each side of the octagon?
8s = 24
s = 3 (each side is 3)
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Cheers,
Stan H.
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