Question 229449: Can you solve ln(x-4) + ln(x+1) = ln (x-8)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! solve ln(x-4) + ln(x+1) = ln (x-8)
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ln[(x-4)(x+1)] = ln(x-8)
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x^2-3x-4 = x-8
x^2-4x+4 = 0
(x-2)^2 = 0
x = 2
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But x cannot be 2 for ln(x-4) would be the natural log of a negative,
which does not exist.
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Conclusion: No solution
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Cheers,
Stan H.
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