SOLUTION: I have a home work problem that I have to solve factor but I don't think it is factorable is ther an alternate way to solve it or is the answer itisn't factorable. X^2+4X+2=0

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I have a home work problem that I have to solve factor but I don't think it is factorable is ther an alternate way to solve it or is the answer itisn't factorable. X^2+4X+2=0       Log On


   

Question 22939: I have a home work problem that I have to solve factor but I don't think it is factorable is ther an alternate way to solve it or is the answer itisn't factorable.
X^2+4X+2=0
(X+ )(X+ )
Found 2 solutions by stanbon!, Earlsdon:
Answer by stanbon!(97) About Me  (Show Source):
You can put this solution on YOUR website!
If you use the quadratic formula you will find
that x= -2+sqrt2 or x= -2-sqrt2
Therefore the factors are (x-(-2+sqrt2)(x-(-2-sqrt2)
You can simplify these but they are the factors.
Cheers,
Stan H.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Yes there is. Quadratic equations are always solvable by using the quadratic formula: x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a
For your equation, this would look like:
x+=+%28-4%2B-sqrt%284%5E2-4%281%29%282%29%29%29%2F2%281%29
x+=+%28-4%2B-sqrt%2816-8%29%29%2F2
x+=+%28-4%2B-sqrt%288%29%29%2F2
x+=+%28-4%2B-2sqrt%282%29%29%2F2
The roots are:
x+=+-2%2Bsqrt%282%29
x+=+-2-sqrt%282%29