Question 229230: I have a math problem where they say sand is poured from a grinder forming a conically shaped pile. When the pile is 28 feet in diameter and 12 feet high, how many cubic yards of sand are in the pile. I have been trying to get the answer using the volume of a cone formula. V= 1/3(3.14)(14)squared(12). I cannot seem to get the answer. Can you help me please? Thank you very much.
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! When the pile is 28 feet in diameter and 12 feet high, how many cubic yards of sand are in the pile.
V = 784*pi cubic feet
V = 784*pi/27 cubic yards
V =~ 91.22 cubic yards
Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
Since the dimensions of the cone are given in feet, i.e. 28 feet base diameter and 12 feet height, when you square the radius, in feet, you get feet squared, then when you multiply by height, in feet, you get feet cubed, or cubic feet. But the problem requires the answer in cubic yards. 3 times 3 times 3 equals 27, so there are
(14)^2(12)\text{ ft^3})
in this cone, but there are
(14)^2(12)}{27}\text{ yd^3})
John
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