SOLUTION: Find the x and y intercept points of -3x-2y=12

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Question 229195: Find the x and y intercept points of -3x-2y=12
Found 3 solutions by rfer, checkley77, drj:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
y int x=0 (0,-6)
x int y=0 (-4,0)
-3x-2y=12
-2y=3x+12
2y=-3x-12
y=(-3x-12)/2
y=-3(0)-12/2
y=-6
(0,-6)
---------------------
-3x=2y+12
3x=-2y-12
x=(-2y-12)/3
x=-2(0)-12/3
x=-4
(-4,0)

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
-3x-2y=12
-2y=3x+12
y=3x/-2+12/-2
y=-3x/2-6
+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-3x%2F2+-6%29+ (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -3x/2 -6).
Intercepts: (-4,0) & (0,-6)

Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
Find the x and y intercept points of -3x-2y=12

Step 1. Intercepts means that the intersect the x or y axis. This means that one of the coordinates is zero. So for x=0, then the point (0,b) has b a the y-intercepts. and for y=0, then the point (a,0) has a as the x-intercept.

Step 2. Then for x=0 in equation-3x-2y=12 we have

-3%2A0-2y=12

-2y=12

Divide by -2 to both sides of the equation

cross%28-2%29y%2Fcross%28-2%29=12%2F-2

y=-6 or b=-6

So we have (0,-6) as one point with b=-6 as the y-intercept.

Step 3. Then for y=0 in equation-3x-2y=12 we have

-3x-2%2A0=12

-3x=12

Divide by -3 to both sides of the equation

cross%28-3%29y%2Fcross%28-3%29=12%2F-3

y=-4 or a=-4

So we have (-4, 0) as one point with a=-4 as the x-intercept.

Step 4. ANSWER: So we have (0,-6) as one point with b=-6 as the y-intercept and we have (-4,0) as one point with a=-4 as the x-intercept.

We can use these two points (-4,0) and (0,-6) to plot the graph.

graph%28400%2C400%2C+-10%2C10%2C+-10%2C+10%2C+-3x%2F2-6%29

I hope the above steps were helpful.

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Good luck in your studies!

Respectfully,
Dr J