SOLUTION: find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 229033: find four consecutive even integers such that the sum of the squares of the first and the second is 12 more than the last
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the smallest integer.

Then is the next consecutive even integer.

The next one after that is

And the last one is

The square of the first one is:

The square of the second one is:

The sum of the squares of the first two is:

Twelve more than the last is

So:





Solve the quadratic for to find the smallest integer, and then count by 2s to get the next three.

Hint: This quadratic factors. You will get two roots, but one of them will not be an integer. The positive integer root is your answer.

John