SOLUTION: solve the equation 4(2t + 5) - 21 + 7t - 6 10 + 5(z-2) = 4z + 1 4(5x + 3) = 2(7x + 6)

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Question 228876: solve the equation
4(2t + 5) - 21 + 7t - 6
10 + 5(z-2) = 4z + 1
4(5x + 3) = 2(7x + 6)


Answer by JenniferTutors(83) About Me  (Show Source):
You can put this solution on YOUR website!
For the equation:
4%282t%2B5%29-21%2B7t-6
You want to multiply 4 into the first parenthesis as follows:
8t%2B20-21%2B7t-6
Now combine like terms, add the t's and the numbers from left to right, and remember to keep the negative sign of the larger number.
15t-7
For the next problem:
10%2B5%28z-2%29=4z%2B1
Here, you want to multiply 5 into the parenthesis:
10%2B5z-10=4z%2B1
Next is to combine like terms on the left side of the equation:
5z=4z%2B1
Now, you want to get z by itself to solve for it, so subtract 4z to the left side of the equation.
z=1
For the last problem:
%284%29%285x%2B3%29=%282%29%287x%2B6%29
You would multiply 4 into the first parenthesis, and multiply 2 in the second parenthesis:
%2820x%2B12%29=%2814x%2B12%29
Next, you want to get x by itself, you can subtract 14x from the right side of the left side of the equation.
%286x%2B12%29=12
Now, you would subtract the 12 (next to 6x) to the other side of the equation to get x by itself.
6x=0
In this case, when you divide by 6 to get x by itself, you're left with 0%2F6
This just equals 0.