SOLUTION: A person has quarters, dimes, and nickels with a total value of 500 cents($5.oo). The number of nickels is twice the number of quarters. The number of dimes is four less then the n

Algebra ->  Linear-equations -> SOLUTION: A person has quarters, dimes, and nickels with a total value of 500 cents($5.oo). The number of nickels is twice the number of quarters. The number of dimes is four less then the n      Log On


   



Question 228872: A person has quarters, dimes, and nickels with a total value of 500 cents($5.oo). The number of nickels is twice the number of quarters. The number of dimes is four less then the number of quarters.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A person has quarters, dimes, and nickels with a total value of 500 cents($5.oo). The number of nickels is twice the number of quarters. The number of dimes is four less then the number of quarters.
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Equations:
Value Equation: 25q + 10d + 5n = 500 cents
Quantity Equat:: n = 2q
Quantity Equat:: d = q-4
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Substitute to get:
25q + 10(q-4) + 5(2q) = 500
25q + 10q - 40 + 10q = 500
45q = 540
q = 12 (# of quarters)
n = 2q = 24 (# of nickels)
d = q-4 = 8 (# of dimes)
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Cheers,
Stan H.