Question 228817: find the eighth term of the geometric sequence; 432, -216, 108,...
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! find the eighth term of the geometric sequence; 432, -216, 108,...
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r = (-216/432 = -0.5
a(1) = 432
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a(8) = a(1)*r(n-1)
a(8) = 432*(-.5)^7 = -27/8
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Cheers,
Stan H.
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