Question 228498: 2. Two runners are separated by 1/2 mile at the time they both stopped their run. The faster runner ran at a rate of 5 mph and the slower runner at a rate of 4 mph. What distance did the faster runner cover?
Answer by drj(1380)   (Show Source):
You can put this solution on YOUR website! 2. Two runners are separated by 1/2 mile at the time they both stopped their run. The faster runner ran at a rate of 5 mph and the slower runner at a rate of 4 mph. What distance did the faster runner cover?
Step 1. distance= speed * time
Step 2. Let t be the amount of time ran by by each runners.
Step 3. Let 5t be the distance of the faster runner at 5 miles per hour (mph).
Step 4. Let 4t be the distance of the slower runner at 4 mph.
Step 5. Then 5t-4t=0.5 or t=1/2 hour since the runners are separated by 1/2 mile.
Step 6. So 5t=2.5 miles and 4t=2 miles.
Step 7. ANSWER: The faster runner traveled a distance of 2.5 miles.
Hello,
You're welcome and I'm glad that I could help in some way.
Good luck in your studies!
Cheers,
Dr J
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
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