SOLUTION: A mixture of 10% acid and 90% water is added to 5 liters of pure acid. the final mixture is 40% water . How many liters of water are in the final mixture? thanks

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Question 228403: A mixture of 10% acid and 90% water is added to 5 liters of pure acid. the final mixture is 40% water . How many liters of water are in the final mixture?
thanks
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A mixture of 10% acid and 90% water is added to 5 liters of pure acid.
The final mixture is 40% water.
How many liters of water are in the final mixture?
:
Let x = amt of acid/water mixture added
;
Write an amt of water equation
.90x = .40(x + 5)
.90x = .40x + 2
.9x - .4x = 2
.5x = 2
x = 2%2F.5
x = 4 liters of 90% water mixture added to the 5 liters of pure acid
:
Find the amt of water in the final mixture
w = .4(4+5)
w = .4(9)
w = 3.6 liters is water in the final mixture