SOLUTION: Pleace help me solve. I tried dividing 126 by four and adding 15 inches, but that was really off. A perimeter of a rectangle is 126 inches. The lenght exceeds the width by 1

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Pleace help me solve. I tried dividing 126 by four and adding 15 inches, but that was really off. A perimeter of a rectangle is 126 inches. The lenght exceeds the width by 1      Log On


   

Question 228291: Pleace help me solve.
I tried dividing 126 by four and adding 15 inches, but that was really off.
A perimeter of a rectangle is 126 inches. The lenght exceeds the width by 15 inches. Find the lengh and width.
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
126=2x+2(x+15)
126=2x+2x+30
96=4x
x=24
x+15=39
P=2w+2L