SOLUTION: For what values of p will one root of {{{p(x^2+1)=8x-1}}} be three times the other root?

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Question 228262: For what values of p will one root of p%28x%5E2%2B1%29=8x-1 be three times the other root?
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Let's first look at a plan. Let's call one of the roots, r. Then the other root, being three times as much, would be 3r. And an equation which has r and 3r as roots would be %28x-r%29%28x-3r%29+=+0. (Think this out and make sure you see why, if x was r or 3r, then it would fit this equation.) If we simplify this equation we get: x%5E2+-4rx+%2B+3r%5E2+=+0

Our plan then is to rearrange your equation into this form and then figure out what "P" would have to be. So we'll start by dividing both sides by p:
x%5E2+%2B+1+=+%288%2Fp%29x+-+1%2Fp
Next we'll subtract %288%2Fp%29x form each side:
x%5E2+-+%288%2Fp%29x+%2B+1+=+-1%2Fp
Now we'll add 1%2Fp%7D%7D+to+each+side%3A%0D%0A%7B%7B%7Bx%5E2+-+%288%2Fp%29x+%2B+%281%2B1%2Fp%29+=+0
We want this equation
x%5E2+-+%288%2Fp%29x+%2B+%281%2B1%2Fp%29+=+0
to match the pattern of
x%5E2+-4rx+%2B+3r%5E2+=+0
This must mean that
8%2Fp+=+4r so the coefficients of x match
and
%281%2B1%2Fp%29+=+3r%5E2 so the constant terms match.
We now have a system of two equations with two variables. We should be able to solve this system. Since the equations are not linear, probably the Substitution Method is best. So we'll start by solving one of the equations for one of the variables. It looks to me that solving the first equation for r is easiest. We just have to divide both sides of the equation by 4:
2%2Fp+=+r
Now we'll substitute this into the second equation:
%281%2B1%2Fp%29+=+3%282%2Fp%29%5E2
And solve it:
1+%2B+1%2Fp+=+3%284%2Fp%5E2%29
1+%2B+1%2Fp+=+12%2Fp%5E2
Multiply both sides by the Lowest Common Denominator (lcd) to get rid of the fractions:
p%5E2%281%2B1%2Fp%29+=+p%5E2%2812%2Fp%5E2%29
p%5E2+%2B+p+=+12
This is a quadratic equation to we'll get one side equal to zero:
p%5E2+%2B+p+-+12+=+0
and factor it:
%28p%2B4%29%28p-3%29+=+0
and solve it:
p%2B4+=+0 or p-3+=+0
p+=+-4 or p+=+3

You can check these answers, one at a time, by substituting the value for p into your original equation and finding its roots. You should find that for each value of p that one root is three times the other. I'll leave this up to you.