SOLUTION: The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of e
Algebra ->
Equations
-> SOLUTION: The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of e
Log On
Question 228242: The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of each rectangle. Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The length of a red rectangle is 15 cm more than its width w. A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has perimeter 72 cm. Find the dimensions of each rectangle.
Step 1. Perimeter P means adding up all 4 sides of a rectangle.
Step 2. Let w be the width of the red rectangle
Step 3. Let w+15 be the length of the red rectangle
Step 4. Let w+5 be the width of the blue rectangle
Step 5. Let w+15-2=w+13 be the length of the blue rectangle
Step 6. Then for the blue rectangle, P=w+5+w+5+w+13+w+13=4w+36=72
Step 7. Solving 4w+36=72 using the following steps
Subtract 36 from both sides of the equation
Divide by 4 to both sides of the equation
and
and And which is a true statement
Step 5. ANSWER: For the red triangle the width is 9 cm and the length is 24 cm. For the blue triangle, the width is 14 cm and the length is 22 cm.
I hope the above steps were helpful.
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
