Question 228196: The sum of three consecutive integers is 47 less than the least of the integers. Show work to understand Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The sum of three consecutive integers is 47 less than the least of the integers. Show work to understand.
Step 1. Let n be the first and the least of the integers.
Step 2. Let n+1 and n+2 be the next two consecutive integers.
Step 3. Let n+n+1+n+2 be the sum of the three consecutive integers.
Step 4. Let n-47 be 47 less than the least of the integers
Step 5. Then n+n+1+n+2=n-47 since the sum of three consecutive integers is 47 less than the least of the integers
Step 6. Solving n+n+1+n+2=n-47 leads to the following steps
Subtract 3 from both sides of the equation
Subtract n from both sides of the equation
Divide by 2 to both sides of the equation
and
Check if sum if 47 less than the least.
which is a true statement
Step 7. ANSWER: The three consecutive numbers are -25, -24, and -23.
I hope the above steps were helpful.
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