SOLUTION: solve and graph [3x - 8] >2 I used "[]" in the replacement of the ABSLOUTE VALUE bars I couldn't find them on the key board

Algebra ->  Absolute-value -> SOLUTION: solve and graph [3x - 8] >2 I used "[]" in the replacement of the ABSLOUTE VALUE bars I couldn't find them on the key board       Log On


   



Question 228187: solve and graph

[3x - 8] >2
I used "[]" in the replacement of the ABSLOUTE VALUE bars I couldn't find them on the key board

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

abs%283x-8%29%3E2 Start with the given inequality


Break up the absolute value (remember, if you have abs%28x%29%3E+a, then x+%3C+-a or x+%3E+a)

3x-8+%3C+-2 or 3x-8+%3E+2 Break up the absolute value inequality using the given rule




Now lets focus on the first inequality 3x-8+%3C+-2


3x-8%3C-2 Start with the given inequality


3x%3C-2%2B8Add 8 to both sides


3x%3C6 Combine like terms on the right side


x%3C%286%29%2F%283%29 Divide both sides by 3 to isolate x



x%3C2 Divide


Now lets focus on the second inequality 3x-8+%3E+2


3x-8%3E2 Start with the given inequality


3x%3E2%2B8Add 8 to both sides


3x%3E10 Combine like terms on the right side


x%3E%2810%29%2F%283%29 Divide both sides by 3 to isolate x



x%3E10%2F3 Reduce



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Answer:

So our answer is

x+%3C+2 or x+%3E+10%2F3


which looks like this in interval notation





if you wanted to graph the solution set, you would get

Graph of the solution set in blue and the excluded values represented by open circles