SOLUTION: Good Evening, I am working on solving this problem. Please help. I'm still confused on the process. 4^x+1=64 Where appropriate, include approximations to the nearest thousan

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Good Evening, I am working on solving this problem. Please help. I'm still confused on the process. 4^x+1=64 Where appropriate, include approximations to the nearest thousan      Log On


   



Question 22792: Good Evening, I am working on solving this problem. Please help. I'm still confused on the process.
4^x+1=64 Where appropriate, include approximations to the nearest thousandth.

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
I assume that the use of logarithms is expected.
4%5Ex+%2B+1+=+64 Subtract 1 from both sides of the equation.
4%5Ex+=+63 Take the log of both sides.
xlog4+=+log63 Divide both sides by log4
x+=+%28log63%29%2Flog4 You can do this on your calculator or use a table of logarithms.
x+=+2.989 to the nearest thousandth.
Check:
4%5E%282.989%29+%2B+1+=+63.031+%2B+1 = 64.031