SOLUTION: The perimeter of a rectangle is 106 inches. The length exceeds the width by 45 inches. Find the length and the width. The length is ____ inches. (Type an integer or a decimal)

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Question 227778: The perimeter of a rectangle is 106 inches. The length exceeds the width by 45 inches. Find the length and the width.
The length is ____ inches.
(Type an integer or a decimal)
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter of a rectangle is 106 inches. The length exceeds the width by 45 inches. Find the length and the width.

The length is 49 inches.

(Type an integer or a decimal)

Step 1. The perimeter P means adding up all the four sides of a rectangle.

Step 2. Let w be the width.

Step 3. Let w+45 be the length

Step 4. Then, P=w+w+w+45+w+45=106.

Step 5. Solving yields the following steps

4w%2B90=106

Subtract 90 form both sides of the equation

4w%2B90-90=106-90

4w=16

Divide by 4 to both sides of the equation.

4w%2F4=16%2F4

w=4

For w=4 , then w%2B4=49 and check P=2%284%2B49%29=106 which is a true statement.

Step 6. ANSWER: The length is 49 inches.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J