SOLUTION: I can get the equation and solve this but i am unsure how to apply it to get the dimensions of the rectangle. The problem is this: Find the dimensions of a rectangle whose width i

Algebra ->  Rectangles -> SOLUTION: I can get the equation and solve this but i am unsure how to apply it to get the dimensions of the rectangle. The problem is this: Find the dimensions of a rectangle whose width i      Log On


   



Question 227710: I can get the equation and solve this but i am unsure how to apply it to get the dimensions of the rectangle. The problem is this:
Find the dimensions of a rectangle whose width is 7 feet less than its length and whose area is 120 square feet.
I was able to get the formula but am unsure how to get the dimensions.

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = length of the rectangle.
Since the width is 7 feet less, the width would be:
x - 7
Area of all rectangles is length * width (A = l*w). Substituting our expressions and the value for the ares of this rectangle we get:
120+=+%28x%29%28x-7%29
Now we solve this. Start by simplifying it (with the Distributive Property):
120+=+x%5E2+-7x
Since this is a quadratic equation, get one side equal to zero (by subtracting 120 from each side):
0+=+x%5E2+-7x+-120
Now we can either factor this or use the quadratic formula:
0+=+%28x+-+15%29%28x%2B8%29
Now we use the Zero Product Property which tells us that this (or any) product can be zero only if one of the factors is zero. So:
x-15+=+0 or x%2B8+=+0
Solving these we get:
x+=+15 or x+=+-8
Since x represents the length of the rectangle we must reject the negative answer. So the only possible length is 15. And the width, which is x-7, is 8.