SOLUTION: Can someone PLEASE help me!!! What is the value of X in the equation:
log{{{3}}}X = (1/2)log{{{3}}}25-5log{{{3}}}2 Thanks for all the help. By the way 1/2 is the fraction one hal
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-> SOLUTION: Can someone PLEASE help me!!! What is the value of X in the equation:
log{{{3}}}X = (1/2)log{{{3}}}25-5log{{{3}}}2 Thanks for all the help. By the way 1/2 is the fraction one hal
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Question 22746: Can someone PLEASE help me!!! What is the value of X in the equation:
logX = (1/2)log25-5log2 Thanks for all the help. By the way 1/2 is the fraction one half. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Moving everything to the left side of the equal sign you get:
log x -(1/2)log 25 + 5log2 =0 (Note: all terms are base 3)
Applying the laws of logs you get:
log [x(2^5)/sqrt 25]=0
log [32x/5] = 0 (Remember the base is 3)
Therefore:
32x/5 = 3^0
32x = 5
x = 5/32
This is only one way to do the problem. If you know
your log laws you probably can figure out several other
ways to get the same answer.
Cheers,
Stan H.
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