SOLUTION: How many millimeters of pure acid must be added to 120 milliliters of a 30% acid solution to obtain a 50% solution?

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Question 227284: How many millimeters of pure acid must be added to 120 milliliters of a 30% acid solution to obtain a 50% solution?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
.30*120+x=.50(120+x)
36+x=60+.5x
x-.5x=60-36
.5x=24
x=24/.5
x=48 ml of pure acid is used.
Proof:
.30*120+48=.5(120+48)
36+48=.5*168
84=84