SOLUTION: A car leaves a town traveling at 40 miles per hour. Two hours later a second car leaves traveling the same route and overtakes the first car in 5 hours. How fast was the second tra

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Question 227082: A car leaves a town traveling at 40 miles per hour. Two hours later a second car leaves traveling the same route and overtakes the first car in 5 hours. How fast was the second traveling?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Assume I have a stopwatch, and I start it
when the 2nd car leaves
How far has the 1st car gone when I start
the stopwatch?
40%2A2+=+80 mi
The key to the problem is that, after the
stopwatch starts, both cars will travel
for the same amount of time
Let d = distance 2nd car must go to
catch 1st car in mi
Let s = speed of 2nd car in mi/hr
For 1st car:
(1) d+-+80+=+40%2A5
For 2nd car:
(2) d+=+s%2A5
This is 2 equations and 2 unknowns, so it's solvable
(1) d+-+80+=+40%2A5
d+=+80+%2B+200
d+=+280 mi
And, substituting,
(2) d+=+s%2A5
280+=+5s
s+=+56
The speed of the 2nd car was 56 mi/hr