SOLUTION: THE DIFFERENCE OF THE DIGITS OF A TWO-DIGIT NUMBER IS 3. THE TENS' DIGIT IS 1 MORE THAN TWICE THE ONES' DIGIT. WHAT IS THE NUMBER?

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Question 226992: THE DIFFERENCE OF THE DIGITS OF A TWO-DIGIT NUMBER IS 3. THE TENS' DIGIT IS 1 MORE THAN TWICE THE ONES' DIGIT. WHAT IS THE NUMBER?

Found 2 solutions by chibisan, jsmallt9:
Answer by chibisan(131) About Me  (Show Source):
You can put this solution on YOUR website!
in the digit
the tens' digit = 2x, the ones' digit=x
2x-x = 3
x =3

so, the tens' digit is 3*2 = 6
the number is 63.

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the tens digit
Let y = the ones digit
"The difference of the digits of a two digit number is 3". Difference means subtract and with subtraction we have to get the order right. From the next sentence "The tens digit is 1 more than twice the ones digit" we can tell that the tens digit is bigger. So "The difference of the digits of a two digit number is 3" translates into the equation:
x+-+y+=+3
And the sentence "The tens digit is 1 more than twice the ones digit" translates into:
x+=+1+%2B+2y
Now we have two equations with two variables. We can solve this system using a wide variety of methods. Since the second equation is "solved for x" I'll use the Substitution Method. I'll substitute the expression for "x" in the second equation into the first equation:
%281%2B2y%29+-+y+=+3
Simplifying we get:
1+%2B+y+=+3
Subtracting 1 from each side:
y+=+2
Now we can take this value for y and find x, using one of the original equations:
x+=+1+%2B+2%282%29
x+=+1+%2B+4
x+=+5
Since "x" was the tens digit and "y" was the ones digit, our two digit number is: 52.