SOLUTION: System of equations: A laboratory assistant is asked to mix 30% alcohol solution with 21 liters of an 80% alcohol solutuion to make a 60% alcohol solution. How many liters of th

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Question 226451: System of equations:
A laboratory assistant is asked to mix 30% alcohol solution with 21 liters of an 80% alcohol solutuion to make a 60% alcohol solution. How many liters of the the 30% alcohol solution should be used.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = liters of 30% solution to be used
In words:
(liters of alcohol I end up with)/(total liters at end) = 60%
given:
I am adding .3x liters of alcohol to solution
The solution already contains .8%2A21+=+16.8 liters alcohol
I can now write the equation
%28.3x+%2B+16.8%29%2F%2821+%2B+x%29+=+.6
.3x+%2B+16.8+=+.6%2A%2821+%2B+x%29
.3x+%2B+16.8+=+12.6+%2B+.6x
.3x+=+16.8+-+12.6
.3x+=+4.2
x+=+14
14 liters of the 30% solution must be added
check:
%28.3x+%2B+16.8%29%2F%2821+%2B+x%29+=+.6
%28.3%2A14+%2B+16.8%29%2F%2821+%2B+14%29+=+.6
%284.2+%2B+16.8%29%2F35+=+.6
21%2F35+=+.6
21+=+.6%2A35
21+=+21
OK