Question 226395: if a basketball player has a vertical leap of about 20 inches. what is his hang time?use the hang-time function v=48t^2 Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! The problem gives you:
v=48t^2
where
v is "vertical leap" (in inches)
t is time (in seconds)
.
Plug in the given "vertical leap" of 20 inches and solve for t:
v=48t^2
20=48t^2
20/48 = t^2
0.645 seconds = t (hang time)
