SOLUTION: The area of a circle 8 inches in diameter is greater than the combined areas of a circle 6 inches in diameter and a circle 2 inches in diameter by approximately how many square inc

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Question 226384: The area of a circle 8 inches in diameter is greater than the combined areas of a circle 6 inches in diameter and a circle 2 inches in diameter by approximately how many square inches?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
area of a circle is equal to pi%2Ar%5E2
r equals diameter / 2

Circle 1 has a radius of 8/2 = 4 inches.
Circle 2 has a radius of 6/2 = 3 inches.
Circle 3 has a radius of 2/2 = 1 inch.

Area of circle 1 equals pi%2A4%5E2 = 16*pi

Area of circle 2 equals pi%2A3%5E2 = 9*pi

Area of circle 3 equals pi%2A1%5E2 = 1*pi

Differences in the areas is (16-9-1)*pi equals 6*pi equals 18.84955592 square inches.