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Question 226268: The sum of four consecutive odd integers is 216 . Find the four integers
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The sum of four consecutive odd integers is 216 . Find the four integers
Step 1. Let n be the first odd integer.
Step 2. Let n+2, n+4, and n+6 be the next three consecutive odd integers
Step 3. Then, n+n+2+n+4+n+6=216 since the sum of the four consecutive odd integers is 216.
Step 4. Solving the equation in Step 4 yields the following steps
Solved by pluggable solver: EXPLAIN simplification of an expression |
Your Result:
YOUR ANSWER
- This is an equation! Solutions: n=51.
- Graphical form: Equation
was fully solved. - Text form: n+n+2+n+4+n+6=216 simplifies to 0=0
- Cartoon (animation) form:
For tutors: simplify_cartoon( n+n+2+n+4+n+6=216 )
- If you have a website, here's a link to this solution.
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DETAILED EXPLANATION
Look at . Added fractions or integers together It becomes .
Look at . Moved to the right of expression It becomes .
Look at . Eliminated similar terms , , , replacing them with  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Remove unneeded parentheses around factor  It becomes .
Look at . Moved these terms to the left  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Removed extra sign in front of  It becomes .
Look at . Solved linear equation equivalent to 4*n-204 =0 It becomes . Result: 
This is an equation! Solutions: n=51.
Universal Simplifier and Solver
Done!
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With n=51, then n+2=53, n+4=55, and n+6=57. Also 51+53+55+57=216 as a check...
Step 5. The four consecutive odd integers are 51, 53, 55, and 57
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
drjctu@gmail.com
http://www.FreedomUniversity.TV
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