SOLUTION: The sum of four consecutive odd integers is 216 . Find the four integers

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Question 226268: The sum of four consecutive odd integers is 216 . Find the four integers
Answer by drj(1380) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of four consecutive odd integers is 216 . Find the four integers

Step 1. Let n be the first odd integer.

Step 2. Let n+2, n+4, and n+6 be the next three consecutive odd integers

Step 3. Then, n+n+2+n+4+n+6=216 since the sum of the four consecutive odd integers is 216.

Step 4. Solving the equation in Step 4 yields the following steps

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: n=51.
  • Graphical form: Equation n%2Bn%2B2%2Bn%2B4%2Bn%2B6=216 was fully solved.
  • Text form: n+n+2+n+4+n+6=216 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+n%2Bn%2B2%2Bn%2B4%2Bn%2B6=216+%29
    For tutors: simplify_cartoon( n+n+2+n+4+n+6=216 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at n%2Bn%2Bhighlight_red%28+2+%29%2Bn%2Bhighlight_red%28+4+%29%2Bn%2Bhighlight_red%28+6+%29=216.
Added fractions or integers together
It becomes n%2Bn%2Bhighlight_green%28+12+%29%2Bn%2Bn=216.

Look at n%2Bn%2Bhighlight_red%28+12+%29%2Bn%2Bn=216.
Moved 12 to the right of expression
It becomes n%2Bn%2Bn%2Bn%2Bhighlight_green%28+12+%29=216.

Look at .
Eliminated similar terms highlight_red%28+n+%29,highlight_red%28+n+%29,highlight_red%28+n+%29,highlight_red%28+n+%29 replacing them with highlight_green%28+%281%2B1%2B1%2B1%29%2An+%29
It becomes highlight_green%28+%281%2B1%2B1%2B1%29%2An+%29%2B12=216.

Look at .
Added fractions or integers together
It becomes %28highlight_green%28+4+%29%29%2An%2B12=216.

Look at highlight_red%28+%28highlight_red%28+4+%29%29%2An+%29%2B12=216.
Remove unneeded parentheses around factor highlight_red%28+4+%29
It becomes highlight_green%28+4+%29%2An%2B12=216.

Look at 4%2An%2B12=highlight_red%28+216+%29.
Moved these terms to the left highlight_green%28+-216+%29
It becomes 4%2An%2B12-highlight_green%28+216+%29=0.

Look at 4%2An%2Bhighlight_red%28+12+%29-highlight_red%28+216+%29=0.
Added fractions or integers together
It becomes 4%2An%2Bhighlight_green%28+-204+%29=0.

Look at 4%2An%2Bhighlight_red%28+-204+%29=0.
Removed extra sign in front of -204
It becomes 4%2An-highlight_green%28+204+%29=0.

Look at highlight_red%28+4%2An-204+%29=0.
Solved linear equation highlight_red%28+4%2An-204=0+%29 equivalent to 4*n-204 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: n=51.

Universal Simplifier and Solver


Done!



With n=51, then n+2=53, n+4=55, and n+6=57. Also 51+53+55+57=216 as a check...

Step 5. The four consecutive odd integers are 51, 53, 55, and 57


I hope the above steps were helpful.

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And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

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