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Question 226182: the sum of three consecutive integers is -129. find the integers.
Answer by drj(1380) (Show Source):
You can put this solution on YOUR website! The sum of three consecutive integers is -129. Find the integers.
Step 1. Let n be the first integer.
Step 2. Let n+1 and n+2 be the next two consecutive integers.
Step 3. Then, n+n+1+n+2=-129 since the sum is -129.
| Solved by pluggable solver: EXPLAIN simplification of an expression |
Your Result:
YOUR ANSWER
- This is an equation! Solutions: n=-44.
- Graphical form: Equation
was fully solved. - Text form: n+n+1+n+2=-129 simplifies to 0=0
- Cartoon (animation) form:
For tutors: simplify_cartoon( n+n+1+n+2=-129 )
- If you have a website, here's a link to this solution.
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DETAILED EXPLANATION
Look at . Added fractions or integers together It becomes .
Look at . Moved to the right of expression It becomes .
Look at . Eliminated similar terms , , replacing them with  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Remove unneeded parentheses around factor  It becomes .
Look at . Moved these terms to the left  It becomes .
Look at . Added fractions or integers together It becomes .
Look at . Solved linear equation equivalent to 3*n+132 =0 It becomes . Result: 
This is an equation! Solutions: n=-44.
Universal Simplifier and Solver
Done!
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With n=-44, n+1=-43, and n+2=-42. Not the sum of these integers is -129.
Step 4. The integers are -44, -43, and -42.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J
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