SOLUTION: Show that {{{1/(sqrt(a)+sqrt(a+1))}}}={{{sqrt(a+1)-sqrt(a)}}}
Hence, deduce the value of {{{ 1/(sqrt(1)+sqrt(2))}}} + {{{1/(sqrt(2)+sqrt(3))}}} + {{{1/(sqrt(3)+sqrt(4))}}} + ... +
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Matrices-and-determiminant
-> SOLUTION: Show that {{{1/(sqrt(a)+sqrt(a+1))}}}={{{sqrt(a+1)-sqrt(a)}}}
Hence, deduce the value of {{{ 1/(sqrt(1)+sqrt(2))}}} + {{{1/(sqrt(2)+sqrt(3))}}} + {{{1/(sqrt(3)+sqrt(4))}}} + ... +
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First, see my lesson on Rationalizing The Denominator: http://www.algebra.com/algebra/homework/Radicals/rationalizingdenominators1.lesson
The multiplier that is necessary for this particular problem is:
Once you convert all the terms using the rule just developed, and collect like terms, you will notice that all of the terms will disappear except for -1 and , hence the sum is 2.