SOLUTION: how do you solve this equation: x^4-8x^2+12=0
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Question 225769
:
how do you solve this equation: x^4-8x^2+12=0
Answer by
edjones(8007)
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x^4-8x^2+12=0
(x^2-6)(x^2-2)=0
.
x^2=6
x=+-sqrt(6)
.
x^2=2
x=+-sqrt(2)
.
four answers altogether
.
Ed