SOLUTION: This is the last one. u2 - 13u + 40/3u2 - 33u + 90 This is one big fraction again. the 2's after both u's are 'to the power 2's" Again I just do not no where to start.

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Question 225722: This is the last one. u2 - 13u + 40/3u2 - 33u + 90 This is one big fraction again. the 2's after both u's are 'to the power 2's" Again I just do not no where to start.
Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
%28u2+-+13u+%2B+40%29%2F%283u2+-+33u+%2B+90%29
Have to factor the num. and den.:
So, the num. factors with 8 and 5, which add to give us the 13:
%28u-8%29%28u-5%29
The den. has a GCF of 3, so pull that out first:
3%28u%5E2-11%2B30%29
Then factor the remaining bit with 6 and 5, which add to give us the 11:
3%28u-6%29%28u-5%29
Rewrite as a fraction:
%28%28u-8%29%28u-5%29%29%2F%283%28u-6%29%28u-5%29%29
Here we can see that the u-5 cancels, which leaves:
%28%28u-8%29%29%2F%283%28u-6%29%29