SOLUTION: find an integer such that square of the integer is eighty one less than eigtheen times the integer

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Question 225282: find an integer such that square of the integer is eighty one less than eigtheen times the integer
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
x^2=18x-81
x^2-18x+81=0
(x-9)^2=0
x-9=0
x=9 ans.
Proof:
9^2=18*9-81
81=162-81
81=81