SOLUTION: 3x^2+3x+13=0 i would like to see how you worked it out please

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Question 225280: 3x^2+3x+13=0
i would like to see how you worked it out please
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3x^2+3x+13=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(-3+-sqrt[3^2-4*3*13])/2*3
x=(-3+-sqrt[9-156])/6
x=(-3+-sqrt-147)/6
x=(-3+-12.124i)/6
x=-3/6+-2.207i ans.