SOLUTION: Advance tickets to a show cost 20 ,and same-day tickets cost 30. The total number of tickets sold was 60 for total receipts of 1600. How many tickets of each type were sold.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Advance tickets to a show cost 20 ,and same-day tickets cost 30. The total number of tickets sold was 60 for total receipts of 1600. How many tickets of each type were sold.       Log On


   

Question 225216: Advance tickets to a show cost 20 ,and same-day tickets cost 30. The total number of tickets sold was 60 for total receipts of 1600. How many tickets of each type were sold.

Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
From the given information we can say:
A%2BS=60
20A%2B30S=1600
Where A is the advance ticket and S is the same-day ticket.
Solve the first equation for one of the variables:
A=60-S
Then plug this into the second equation:
20%2860-S%29%2B30S=1600
Distribute the 20:
1200-20S%2B30S=1600
Move the 1200 to the other side and combine the S terms:
10S=400
Divide both sides by 10:
S=40
Plug this back into our first equation:
A=60-40=20
So, 40 same-day tickets were sold and 20 advance tickets.