Question 224993: I am stumped on these two and this is what I need to figure out.
1. 4X2 - 4X+3= 0
2. X2+12X-64=0
a. move the constant term to the right side of the equation
b. multiply each term in the equation by four times the cofficient of the x2 term
c. square the coefficient of the original x term and add it to both sides of the equation
d. take the square root of both sides
e. set the left side of the equation equal to the positive square root of the number on the right side and slove for x
f. set the left side of the equation equal to the negative square root of the number on the right side of the equation and slove for x
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! (1) 4x^2 -4x +3=0,,,,solve using quadratic formula
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a=4,,,,b=(-4),,,,,,c=3
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x=[-(-4) +/- sqrt{ (-4)^2 -4 (4)(3)}]/2(4)
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x=[ 4 +/- sqrt -32 ] /8
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x= 1/2 +/- 5.7i/8
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x= .5 + .707i,,,,.5 - .707i
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check,,4(.5+.707i)^2 -4(.5+.707i) +3=0
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4(.25 +.707i -.5) -2 - 2,828i +3 =0
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1 + 2.828i -2-2 -2.828i +3 =0
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1-2-2+3=0,,,,,,,,,, ok
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(2) x^2 +12x -64 = 0,,,,,factor
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(x+16)(x-4) = 0
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x= 4,,,-16
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check,,,(4),,,16 +48 -64 =0,,,,ok
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(-16),,,256 - 192 -64 =0,,,,,ok
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