SOLUTION: Subtact {{{-5ab^2+3a^2b^2-a^2b}}} from {{{7a^2b^2-ab-2ab^2}}} The two behind the a and b are expontents

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Subtact {{{-5ab^2+3a^2b^2-a^2b}}} from {{{7a^2b^2-ab-2ab^2}}} The two behind the a and b are expontents      Log On


   

Question 224851: Subtact -5ab%5E2%2B3a%5E2b%5E2-a%5E2b from 7a%5E2b%5E2-ab-2ab%5E2
The two behind the a and b are expontents
Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
So, set up our problem:
7a%5E2b%5E2-ab-2ab%5E2-%28-5ab%5E2%2B3a%5E2b%5E2-a%5E2b%29
We need to distribute the - sign to every term in the second part so:
7a%5E2b%5E2-ab-2ab%5E2%2B5ab%5E2-3a%5E2b%5E2%2Ba%5E2b%29
Then we can combine any like terms:
7a%5E2b%5E2-3a%5E2b%5E2=4a%5E2b%5E2
-2ab%5E2%2B5ab%5E2=3ab%5E2
both the -ab and tje a%5E2b have no like terms to be combined with, so they are left alone.
These answers all yield the final equation of:
4a%5E2b%5E2%2B3ab%5E2-ab%2Ba%5E2b