SOLUTION: {{{(-7x^3+6x^2-11x+13)+(19x^3-11x^2+7x-17)}}} The threes and twos are expontent

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: {{{(-7x^3+6x^2-11x+13)+(19x^3-11x^2+7x-17)}}} The threes and twos are expontent      Log On


   

Question 224849: %28-7x%5E3%2B6x%5E2-11x%2B13%29%2B%2819x%5E3-11x%5E2%2B7x-17%29
The threes and twos are expontent
Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
All we can do is add our like terms, so x%5E3 and x%5E3 terms can add together, likewise with x%5E2 and keep working down the exponents.
So:
-7x%5E3%2B19x%5E3=12x%5E3
6x%5E2-11x%5E2=-5x%5E2
-11x%2B7x=-4x
13-17=-4
These answers combine to give us our answer of:
12x%5E3-5x%5E2-4x-4