SOLUTION: Divide. {{{(35b^3+18b^2+37b+39)/(5b+4)}}} Thank you!

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Divide. {{{(35b^3+18b^2+37b+39)/(5b+4)}}} Thank you!      Log On


   



Question 224799: Divide. %2835b%5E3%2B18b%5E2%2B37b%2B39%29%2F%285b%2B4%29
Thank you!

Answer by LtAurora(115) About Me  (Show Source):
You can put this solution on YOUR website!
To do this problem, you have to use long division.
Set up the equation with the %2835b%5E3%2B18b%5E2%2B37b%2B39%29 under the division symbol, and the 5b%2B4 on the outside.
The first one to look at is 35b%5E3%2F5b
The answer to this is 7b%5E2.
This we have to multiply back with 5b%2B4 to determine what is going to be subtracted from our equation:
So, we end up with:
%2B35b%5E3%2B18b%5E2 which is from our initial equation
-35b%5E3%2B28b%5E2 which is from multiplying our answer and the 5b%2B4
which is 0-10b%5E2.
We bring down the 37b and have a new equation to evaluate: -10b%5E2%2B37b.
We divide the first term by the 5b again to give us: -2b.
Multiplying this through gives us:
-10b%5E2%2B37b which is from our new equation
%2B10b%5E2%2B8b which is from multiplying our answer and the 5b%2B4
which is 0%2B45b.
We bring down the 3 and have a new equation to evaluate: 45b%2B3
Divide the first term by 5b leaves us with 9.
Multiplying through gives us:
45b%2B3 which is from our new equation
45b%2B36 which is from multiplying our answer and the 5b%2B4
This leaves 39, which is our remainder.
The entire answer after working all this out is:
7b%5E2-2b%2B9%2B39%2F%285b%2B4%29
The 39%2F%285b%2B4%29 is our remainder.