SOLUTION: In 1993, the number of Americans dying from cancer was 6 times the number that died from accidents. If the number of deaths from these two causes totaled 630,000 how many americans

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: In 1993, the number of Americans dying from cancer was 6 times the number that died from accidents. If the number of deaths from these two causes totaled 630,000 how many americans      Log On


   

Question 224580: In 1993, the number of Americans dying from cancer was 6 times the number that died from accidents. If the number of deaths from these two causes totaled 630,000 how many americans died from each cause?
Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
X+6X=630,000
7X=630,000
X=630,000/7
X=90,000 DIED IN ACCIDENTS.
6*90,000=540,000 DIED OF CANCER.
PROOF:
90,000+540,000=630,000
630,000=630,000