SOLUTION: This problem is from the tenth edition Beginning Algebra: Instruction for the problem is Solve each inequality. Write the solution set in interval notation and graph it. I know ho

Algebra ->  Inequalities -> SOLUTION: This problem is from the tenth edition Beginning Algebra: Instruction for the problem is Solve each inequality. Write the solution set in interval notation and graph it. I know ho      Log On


   

Question 224574: This problem is from the tenth edition Beginning Algebra:
Instruction for the problem is Solve each inequality. Write the solution set in interval notation and graph it. I know how to write it in interval notation and how to graph it. I have tried several times to get rid of the fractions and I'm doing something wrong because the answer is (-infinity,32) and I just can't get there. Here is the problem: 2/3(p+3)>5/6(p-4). I know I use the distributive property first and get 2/3p+2>5/6p-10/3.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
2/3(p+3 )> 5/6(p-4)
:
I think the first thing to do is multiply both sides by 6 and get rid of those
fractions. That leaves you with
4(p+3) > 5(p-4)
Now distribute
4p + 12 > 5p - 20
We want the unknowns on the left here
4p - 5p > -20 - 12
-p > -32
Multiply by -1 to get rid of the negative p; when we do that, we have to
reverse the inequality sign.
p < 32