| 
 
 
 
Question 224554:  Write the slope intercept form of the equation of the line described.
 
through:(2,0), parallel to y=1/3x+3 
 Answer by drj(1380)      (Show Source): 
You can  put this solution on YOUR website! Write the slope intercept form of the equation of the line described.
 
through:(2,0), parallel to y=x/3+3
 
 
Step 1.  We can find the slope by recognizing that parallel lines have the same slope.  Since   is in slope-intercept form given as y=mx+b where the slope m=1/3 and the y-intercept b=3 when x=0 or at point (0,b) or (0,3).
 
 
Step 2.  Now we have to find the line with slope m=1/3 going through point (2,0).
 
 
Step 3.  Given two points (x1,y1) and (x2,y2), then the slope m is given as
 
 
 
 
 
Step 4.  Let (x1,y1)=(2,0) or x1=2 and y1=0.  Let other point be (x2,y2)=(x,y) or x2=x and y2=y.
 
 
Step 5.  Now we're given  .  Substituting above values and variables in the slope equation m yields the following steps:
 
 
 
 
 
 
 
 
Step 6.  Multiply x-2 to both sides to get rid of denominator on right side of equation.
 
 
  
 
 
  
 
 
Step 7.  ANSWER:  The equation in slope-intercept form is  
 
 
 
Note:  the above equation can be rewritten as 
 
 
 
 
 
And the graph is shown below which is consistent with the above steps.
 
 
 | Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc |  
Equation   describes a sloping line. For any  
  equation ax+by+c = 0, slope is  .- X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x =  c/a. -2/-1 = 2.
 - Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -2/3 = -0.666666666666667.
 - Slope is --1/3 = 0.333333333333333.
 -  Equation in slope-intercept form: y=0.333333333333333*x+-0.666666666666667.
 
  
 |  
  
 
 
I hope the above steps and explanation were helpful.
 
 
For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
 
 
And good luck in your studies!
 
 
Respectfully, 
Dr J
 
http://www.FreedomUniversity.TV 
 
  | 
 
  
 
 |   
 
 |   
 |  |